2(3x-2)+4(x-2)=6x+28

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Solution for 2(3x-2)+4(x-2)=6x+28 equation: 



2(3x-2)+4(x-2)=6x+28

We move all terms to the left:

2(3x-2)+4(x-2)-(6x+28)=0

We multiply parentheses

6x+4x-(6x+28)-4-8=0

We get rid of parentheses

6x+4x-6x-28-4-8=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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