2(3x-2)+1=10

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Solution for 2(3x-2)+1=10 equation: 



2(3x-2)+1=10

We move all terms to the left:

2(3x-2)+1-(10)=0

We add all the numbers together, and all the variables

2(3x-2)-9=0

We multiply parentheses

6x-4-9=0

We add all the numbers together, and all the variables

6x-13=0

We move all terms containing x to the left, all other terms to the right

6x=13

x=13/6

x=2+1/6

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