2(3x-10)=-4(x+10)

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Solution for 2(3x-10)=-4(x+10) equation: 



2(3x-10)=-4(x+10)

We move all terms to the left:

2(3x-10)-(-4(x+10))=0

We multiply parentheses

6x-(-4(x+10))-20=0



We calculate terms in parentheses: -(-4(x+10)), so:

-4(x+10)

We multiply parentheses

-4x-40

Back to the equation:

-(-4x-40)



We get rid of parentheses

6x+4x+40-20=0

We add all the numbers together, and all the variables

10x+20=0

We move all terms containing x to the left, all other terms to the right

10x=-20

x=-20/10

x=-2

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