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2(3x-10)=(-x+15)
We move all terms to the left:
2(3x-10)-((-x+15))=0
We add all the numbers together, and all the variables
2(3x-10)-((-1x+15))=0
We multiply parentheses
6x-((-1x+15))-20=0
We calculate terms in parentheses: -((-1x+15)), so:We get rid of parentheses
(-1x+15)
We get rid of parentheses
-1x+15
Back to the equation:
-(-1x+15)
6x+1x-15-20=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
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