2(3x-1)+x-x=-2(x+1)+8x

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Solution for 2(3x-1)+x-x=-2(x+1)+8x equation: 



2(3x-1)+x-x=-2(x+1)+8x

We move all terms to the left:

2(3x-1)+x-x-(-2(x+1)+8x)=0

We add all the numbers together, and all the variables

2(3x-1)-(-2(x+1)+8x)=0

We multiply parentheses

6x-(-2(x+1)+8x)-2=0



We calculate terms in parentheses: -(-2(x+1)+8x), so:

-2(x+1)+8x

We add all the numbers together, and all the variables

8x-2(x+1)

We multiply parentheses

8x-2x-2

We add all the numbers together, and all the variables

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

6x-6x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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