2(3x-1)+4x=3(x+2)=7x-8

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Solution for 2(3x-1)+4x=3(x+2)=7x-8 equation: 



2(3x-1)+4x=3(x+2)=7x-8

We move all terms to the left:

2(3x-1)+4x-(3(x+2))=0

We add all the numbers together, and all the variables

4x+2(3x-1)-(3(x+2))=0

We multiply parentheses

4x+6x-(3(x+2))-2=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

10x-(3x+6)-2=0

We get rid of parentheses

10x-3x-6-2=0

We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7

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