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2(3x-1)(x+6)=0
We multiply parentheses ..
2(+3x^2+18x-1x-6)=0
We multiply parentheses
6x^2+36x-2x-12=0
We add all the numbers together, and all the variables
6x^2+34x-12=0
a = 6; b = 34; c = -12;
Δ = b2-4ac
Δ = 342-4·6·(-12)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-38}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+38}{2*6}=\frac{4}{12} =1/3 $
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