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2(3x-)+5=4(x+2)
We move all terms to the left:
2(3x-)+5-(4(x+2))=0
We add all the numbers together, and all the variables
2(+3x)-(4(x+2))+5=0
We multiply parentheses
6x-(4(x+2))+5=0
We calculate terms in parentheses: -(4(x+2)), so:We get rid of parentheses
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
6x-4x-8+5=0
We add all the numbers together, and all the variables
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2
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