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2(3x+6)+9=4-3(2x+5)
We move all terms to the left:
2(3x+6)+9-(4-3(2x+5))=0
We multiply parentheses
6x-(4-3(2x+5))+12+9=0
We calculate terms in parentheses: -(4-3(2x+5)), so:We add all the numbers together, and all the variables
4-3(2x+5)
determiningTheFunctionDomain -3(2x+5)+4
We multiply parentheses
-6x-15+4
We add all the numbers together, and all the variables
-6x-11
Back to the equation:
-(-6x-11)
6x-(-6x-11)+21=0
We get rid of parentheses
6x+6x+11+21=0
We add all the numbers together, and all the variables
12x+32=0
We move all terms containing x to the left, all other terms to the right
12x=-32
x=-32/12
x=-2+2/3
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