2(3x+5)=41

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Solution for 2(3x+5)=41 equation: 



2(3x+5)=41

We move all terms to the left:

2(3x+5)-(41)=0

We multiply parentheses

6x+10-41=0

We add all the numbers together, and all the variables

6x-31=0

We move all terms containing x to the left, all other terms to the right

6x=31

x=31/6

x=5+1/6

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