2(3x+5)=2(7x-27)

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Solution for 2(3x+5)=2(7x-27) equation: 



2(3x+5)=2(7x-27)

We move all terms to the left:

2(3x+5)-(2(7x-27))=0

We multiply parentheses

6x-(2(7x-27))+10=0



We calculate terms in parentheses: -(2(7x-27)), so:

2(7x-27)

We multiply parentheses

14x-54

Back to the equation:

-(14x-54)



We get rid of parentheses

6x-14x+54+10=0

We add all the numbers together, and all the variables

-8x+64=0

We move all terms containing x to the left, all other terms to the right

-8x=-64

x=-64/-8

x=+8

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