2(3x+5)=11(3x-4)

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Solution for 2(3x+5)=11(3x-4) equation: 



2(3x+5)=11(3x-4)

We move all terms to the left:

2(3x+5)-(11(3x-4))=0

We multiply parentheses

6x-(11(3x-4))+10=0



We calculate terms in parentheses: -(11(3x-4)), so:

11(3x-4)

We multiply parentheses

33x-44

Back to the equation:

-(33x-44)



We get rid of parentheses

6x-33x+44+10=0

We add all the numbers together, and all the variables

-27x+54=0

We move all terms containing x to the left, all other terms to the right

-27x=-54

x=-54/-27

x=+2

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