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2(3x+5)=10(x+1)-4x
We move all terms to the left:
2(3x+5)-(10(x+1)-4x)=0
We multiply parentheses
6x-(10(x+1)-4x)+10=0
We calculate terms in parentheses: -(10(x+1)-4x), so:We get rid of parentheses
10(x+1)-4x
We add all the numbers together, and all the variables
-4x+10(x+1)
We multiply parentheses
-4x+10x+10
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
6x-6x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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