2(3x+5)=10(x+1)

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Solution for 2(3x+5)=10(x+1) equation: 



2(3x+5)=10(x+1)

We move all terms to the left:

2(3x+5)-(10(x+1))=0

We multiply parentheses

6x-(10(x+1))+10=0



We calculate terms in parentheses: -(10(x+1)), so:

10(x+1)

We multiply parentheses

10x+10

Back to the equation:

-(10x+10)



We get rid of parentheses

6x-10x-10+10=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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