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2(3x+5)=1/2(2x-4
We move all terms to the left:
2(3x+5)-(1/2(2x-4)=0
Domain of the equation: 2(2x-4)!=0We multiply parentheses
x∈R
6x-(1/2(2x-4)+10=0
We multiply all the terms by the denominator
6x*2(2x-4)+10-(1=0
We add all the numbers together, and all the variables
6x*2(2x-4)=0
Wy multiply elements
12x^2(2=0
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