2(3x+5)=(2x+15)+(6x-37)

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Solution for 2(3x+5)=(2x+15)+(6x-37) equation: 



2(3x+5)=(2x+15)+(6x-37)

We move all terms to the left:

2(3x+5)-((2x+15)+(6x-37))=0

We multiply parentheses

6x-((2x+15)+(6x-37))+10=0



We calculate terms in parentheses: -((2x+15)+(6x-37)), so:

(2x+15)+(6x-37)

We get rid of parentheses

2x+6x+15-37

We add all the numbers together, and all the variables

8x-22

Back to the equation:

-(8x-22)



We get rid of parentheses

6x-8x+22+10=0

We add all the numbers together, and all the variables

-2x+32=0

We move all terms containing x to the left, all other terms to the right

-2x=-32

x=-32/-2

x=+16

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