2(3x+5)-3(x-4)=16

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Solution for 2(3x+5)-3(x-4)=16 equation: 


Simplifying
2(3x + 5) + -3(x + -4) = 16

Reorder the terms:
2(5 + 3x) + -3(x + -4) = 16
(5 * 2 + 3x * 2) + -3(x + -4) = 16
(10 + 6x) + -3(x + -4) = 16

Reorder the terms:
10 + 6x + -3(-4 + x) = 16
10 + 6x + (-4 * -3 + x * -3) = 16
10 + 6x + (12 + -3x) = 16

Reorder the terms:
10 + 12 + 6x + -3x = 16

Combine like terms: 10 + 12 = 22
22 + 6x + -3x = 16

Combine like terms: 6x + -3x = 3x
22 + 3x = 16

Solving
22 + 3x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 3x = 16 + -22

Combine like terms: 22 + -22 = 0
0 + 3x = 16 + -22
3x = 16 + -22

Combine like terms: 16 + -22 = -6
3x = -6

Divide each side by '3'.
x = -2

Simplifying
x = -2

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