2(3x+5)+6x=106

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Solution for 2(3x+5)+6x=106 equation: 



2(3x+5)+6x=106

We move all terms to the left:

2(3x+5)+6x-(106)=0

We add all the numbers together, and all the variables

6x+2(3x+5)-106=0

We multiply parentheses

6x+6x+10-106=0

We add all the numbers together, and all the variables

12x-96=0

We move all terms containing x to the left, all other terms to the right

12x=96

x=96/12

x=8

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