2(3x+5)+2(2x+-2)=106

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Solution for 2(3x+5)+2(2x+-2)=106 equation: 



2(3x+5)+2(2x+-2)=106

We move all terms to the left:

2(3x+5)+2(2x+-2)-(106)=0

We add all the numbers together, and all the variables

2(3x+5)+2(2x-2)-106=0

We multiply parentheses

6x+4x+10-4-106=0

We add all the numbers together, and all the variables

10x-100=0

We move all terms containing x to the left, all other terms to the right

10x=100

x=100/10

x=10

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