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2(3x+4)=-3(3x-4)+4x
We move all terms to the left:
2(3x+4)-(-3(3x-4)+4x)=0
We multiply parentheses
6x-(-3(3x-4)+4x)+8=0
We calculate terms in parentheses: -(-3(3x-4)+4x), so:We get rid of parentheses
-3(3x-4)+4x
We add all the numbers together, and all the variables
4x-3(3x-4)
We multiply parentheses
4x-9x+12
We add all the numbers together, and all the variables
-5x+12
Back to the equation:
-(-5x+12)
6x+5x-12+8=0
We add all the numbers together, and all the variables
11x-4=0
We move all terms containing x to the left, all other terms to the right
11x=4
x=4/11
x=4/11
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