2(3x+4)-x+8=3(4x+2)-7x+10

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Solution for 2(3x+4)-x+8=3(4x+2)-7x+10 equation: 



2(3x+4)-x+8=3(4x+2)-7x+10

We move all terms to the left:

2(3x+4)-x+8-(3(4x+2)-7x+10)=0

We add all the numbers together, and all the variables

-1x+2(3x+4)-(3(4x+2)-7x+10)+8=0

We multiply parentheses

-1x+6x-(3(4x+2)-7x+10)+8+8=0



We calculate terms in parentheses: -(3(4x+2)-7x+10), so:

3(4x+2)-7x+10

We add all the numbers together, and all the variables

-7x+3(4x+2)+10

We multiply parentheses

-7x+12x+6+10

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

5x-(5x+16)+16=0

We get rid of parentheses

5x-5x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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