2(3x+4)-8=4(x-2)

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Solution for 2(3x+4)-8=4(x-2) equation: 



2(3x+4)-8=4(x-2)

We move all terms to the left:

2(3x+4)-8-(4(x-2))=0

We multiply parentheses

6x-(4(x-2))+8-8=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

6x-(4x-8)=0

We get rid of parentheses

6x-4x+8=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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