2(3x+4)-1x-8=3(4x+2)-7x+10

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Solution for 2(3x+4)-1x-8=3(4x+2)-7x+10 equation:


Simplifying
2(3x + 4) + -1x + -8 = 3(4x + 2) + -7x + 10

Reorder the terms:
2(4 + 3x) + -1x + -8 = 3(4x + 2) + -7x + 10
(4 * 2 + 3x * 2) + -1x + -8 = 3(4x + 2) + -7x + 10
(8 + 6x) + -1x + -8 = 3(4x + 2) + -7x + 10

Reorder the terms:
8 + -8 + 6x + -1x = 3(4x + 2) + -7x + 10

Combine like terms: 8 + -8 = 0
0 + 6x + -1x = 3(4x + 2) + -7x + 10
6x + -1x = 3(4x + 2) + -7x + 10

Combine like terms: 6x + -1x = 5x
5x = 3(4x + 2) + -7x + 10

Reorder the terms:
5x = 3(2 + 4x) + -7x + 10
5x = (2 * 3 + 4x * 3) + -7x + 10
5x = (6 + 12x) + -7x + 10

Reorder the terms:
5x = 6 + 10 + 12x + -7x

Combine like terms: 6 + 10 = 16
5x = 16 + 12x + -7x

Combine like terms: 12x + -7x = 5x
5x = 16 + 5x

Add '-5x' to each side of the equation.
5x + -5x = 16 + 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 16 + 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 16 + 0
0 = 16

Solving
0 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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