2(3x+4)+5(4x+1)=41

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Solution for 2(3x+4)+5(4x+1)=41 equation:


Simplifying
2(3x + 4) + 5(4x + 1) = 41

Reorder the terms:
2(4 + 3x) + 5(4x + 1) = 41
(4 * 2 + 3x * 2) + 5(4x + 1) = 41
(8 + 6x) + 5(4x + 1) = 41

Reorder the terms:
8 + 6x + 5(1 + 4x) = 41
8 + 6x + (1 * 5 + 4x * 5) = 41
8 + 6x + (5 + 20x) = 41

Reorder the terms:
8 + 5 + 6x + 20x = 41

Combine like terms: 8 + 5 = 13
13 + 6x + 20x = 41

Combine like terms: 6x + 20x = 26x
13 + 26x = 41

Solving
13 + 26x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 26x = 41 + -13

Combine like terms: 13 + -13 = 0
0 + 26x = 41 + -13
26x = 41 + -13

Combine like terms: 41 + -13 = 28
26x = 28

Divide each side by '26'.
x = 1.076923077

Simplifying
x = 1.076923077

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