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2(3x+3)=-5(4x-5)+3x
We move all terms to the left:
2(3x+3)-(-5(4x-5)+3x)=0
We multiply parentheses
6x-(-5(4x-5)+3x)+6=0
We calculate terms in parentheses: -(-5(4x-5)+3x), so:We get rid of parentheses
-5(4x-5)+3x
We add all the numbers together, and all the variables
3x-5(4x-5)
We multiply parentheses
3x-20x+25
We add all the numbers together, and all the variables
-17x+25
Back to the equation:
-(-17x+25)
6x+17x-25+6=0
We add all the numbers together, and all the variables
23x-19=0
We move all terms containing x to the left, all other terms to the right
23x=19
x=19/23
x=19/23
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