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2(3x+3)=-3(3x-5)+4x
We move all terms to the left:
2(3x+3)-(-3(3x-5)+4x)=0
We multiply parentheses
6x-(-3(3x-5)+4x)+6=0
We calculate terms in parentheses: -(-3(3x-5)+4x), so:We get rid of parentheses
-3(3x-5)+4x
We add all the numbers together, and all the variables
4x-3(3x-5)
We multiply parentheses
4x-9x+15
We add all the numbers together, and all the variables
-5x+15
Back to the equation:
-(-5x+15)
6x+5x-15+6=0
We add all the numbers together, and all the variables
11x-9=0
We move all terms containing x to the left, all other terms to the right
11x=9
x=9/11
x=9/11
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