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2(3x+3)=-3(2x-4)-5x
We move all terms to the left:
2(3x+3)-(-3(2x-4)-5x)=0
We multiply parentheses
6x-(-3(2x-4)-5x)+6=0
We calculate terms in parentheses: -(-3(2x-4)-5x), so:We get rid of parentheses
-3(2x-4)-5x
We add all the numbers together, and all the variables
-5x-3(2x-4)
We multiply parentheses
-5x-6x+12
We add all the numbers together, and all the variables
-11x+12
Back to the equation:
-(-11x+12)
6x+11x-12+6=0
We add all the numbers together, and all the variables
17x-6=0
We move all terms containing x to the left, all other terms to the right
17x=6
x=6/17
x=6/17
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