2(3x+2)=3(2x+1)+1

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Solution for 2(3x+2)=3(2x+1)+1 equation: 



2(3x+2)=3(2x+1)+1

We move all terms to the left:

2(3x+2)-(3(2x+1)+1)=0

We multiply parentheses

6x-(3(2x+1)+1)+4=0



We calculate terms in parentheses: -(3(2x+1)+1), so:

3(2x+1)+1

We multiply parentheses

6x+3+1

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

6x-6x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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