2(3x+1)=x+222(3x+1)=x+22

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Solution for 2(3x+1)=x+222(3x+1)=x+22 equation: 



2(3x+1)=x+222(3x+1)=x+22

We move all terms to the left:

2(3x+1)-(x+222(3x+1))=0

We multiply parentheses

6x-(x+222(3x+1))+2=0



We calculate terms in parentheses: -(x+222(3x+1)), so:

x+222(3x+1)

We multiply parentheses

x+666x+222

We add all the numbers together, and all the variables

667x+222

Back to the equation:

-(667x+222)



We get rid of parentheses

6x-667x-222+2=0

We add all the numbers together, and all the variables

-661x-220=0

We move all terms containing x to the left, all other terms to the right

-661x=220

x=220/-661

x=-220/661

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