2(3x+1)=x+18

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Solution for 2(3x+1)=x+18 equation: 



2(3x+1)=x+18

We move all terms to the left:

2(3x+1)-(x+18)=0

We multiply parentheses

6x-(x+18)+2=0

We get rid of parentheses

6x-x-18+2=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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