2(3x+1)=8(x-7)

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Solution for 2(3x+1)=8(x-7) equation: 



2(3x+1)=8(x-7)

We move all terms to the left:

2(3x+1)-(8(x-7))=0

We multiply parentheses

6x-(8(x-7))+2=0



We calculate terms in parentheses: -(8(x-7)), so:

8(x-7)

We multiply parentheses

8x-56

Back to the equation:

-(8x-56)



We get rid of parentheses

6x-8x+56+2=0

We add all the numbers together, and all the variables

-2x+58=0

We move all terms containing x to the left, all other terms to the right

-2x=-58

x=-58/-2

x=+29

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