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2(3x+1)=5(5x+2)
We move all terms to the left:
2(3x+1)-(5(5x+2))=0
We multiply parentheses
6x-(5(5x+2))+2=0
We calculate terms in parentheses: -(5(5x+2)), so:We get rid of parentheses
5(5x+2)
We multiply parentheses
25x+10
Back to the equation:
-(25x+10)
6x-25x-10+2=0
We add all the numbers together, and all the variables
-19x-8=0
We move all terms containing x to the left, all other terms to the right
-19x=8
x=8/-19
x=-8/19
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