2(3x+1)=4(x-6)+8

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Solution for 2(3x+1)=4(x-6)+8 equation: 



2(3x+1)=4(x-6)+8

We move all terms to the left:

2(3x+1)-(4(x-6)+8)=0

We multiply parentheses

6x-(4(x-6)+8)+2=0



We calculate terms in parentheses: -(4(x-6)+8), so:

4(x-6)+8

We multiply parentheses

4x-24+8

We add all the numbers together, and all the variables

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

6x-4x+16+2=0

We add all the numbers together, and all the variables

2x+18=0

We move all terms containing x to the left, all other terms to the right

2x=-18

x=-18/2

x=-9

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