2(3x+1)=4(x+1)+2x-2

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Solution for 2(3x+1)=4(x+1)+2x-2 equation: 



2(3x+1)=4(x+1)+2x-2

We move all terms to the left:

2(3x+1)-(4(x+1)+2x-2)=0

We multiply parentheses

6x-(4(x+1)+2x-2)+2=0



We calculate terms in parentheses: -(4(x+1)+2x-2), so:

4(x+1)+2x-2

We add all the numbers together, and all the variables

2x+4(x+1)-2

We multiply parentheses

2x+4x+4-2

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

6x-6x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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