2(3x+1)=3+2(2x+1)

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Solution for 2(3x+1)=3+2(2x+1) equation: 



2(3x+1)=3+2(2x+1)

We move all terms to the left:

2(3x+1)-(3+2(2x+1))=0

We multiply parentheses

6x-(3+2(2x+1))+2=0



We calculate terms in parentheses: -(3+2(2x+1)), so:

3+2(2x+1)

determiningTheFunctionDomain
2(2x+1)+3

We multiply parentheses

4x+2+3

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

6x-4x-5+2=0

We add all the numbers together, and all the variables

2x-3=0

We move all terms containing x to the left, all other terms to the right

2x=3

x=3/2

x=1+1/2

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