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2(3x+1)=3(x+4)
We move all terms to the left:
2(3x+1)-(3(x+4))=0
We multiply parentheses
6x-(3(x+4))+2=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
6x-3x-12+2=0
We add all the numbers together, and all the variables
3x-10=0
We move all terms containing x to the left, all other terms to the right
3x=10
x=10/3
x=3+1/3
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