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2(3x+1)=3(2x+5)
We move all terms to the left:
2(3x+1)-(3(2x+5))=0
We multiply parentheses
6x-(3(2x+5))+2=0
We calculate terms in parentheses: -(3(2x+5)), so:We get rid of parentheses
3(2x+5)
We multiply parentheses
6x+15
Back to the equation:
-(6x+15)
6x-6x-15+2=0
We add all the numbers together, and all the variables
-13!=0
There is no solution for this equation
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