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2(3x+1)=-2(4x-5)+3x
We move all terms to the left:
2(3x+1)-(-2(4x-5)+3x)=0
We multiply parentheses
6x-(-2(4x-5)+3x)+2=0
We calculate terms in parentheses: -(-2(4x-5)+3x), so:We get rid of parentheses
-2(4x-5)+3x
We add all the numbers together, and all the variables
3x-2(4x-5)
We multiply parentheses
3x-8x+10
We add all the numbers together, and all the variables
-5x+10
Back to the equation:
-(-5x+10)
6x+5x-10+2=0
We add all the numbers together, and all the variables
11x-8=0
We move all terms containing x to the left, all other terms to the right
11x=8
x=8/11
x=8/11
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