2(3x+1)+5=(x-1)

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Solution for 2(3x+1)+5=(x-1) equation: 



2(3x+1)+5=(x-1)

We move all terms to the left:

2(3x+1)+5-((x-1))=0

We multiply parentheses

6x-((x-1))+2+5=0



We calculate terms in parentheses: -((x-1)), so:

(x-1)

We get rid of parentheses

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

6x-(x-1)+7=0

We get rid of parentheses

6x-x+1+7=0

We add all the numbers together, and all the variables

5x+8=0

We move all terms containing x to the left, all other terms to the right

5x=-8

x=-8/5

x=-1+3/5

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