2(3x+1)+4-3(4x+2)-5+4(5x-3)-5(6x-4)=-29

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Solution for 2(3x+1)+4-3(4x+2)-5+4(5x-3)-5(6x-4)=-29 equation: 



2(3x+1)+4-3(4x+2)-5+4(5x-3)-5(6x-4)=-29

We move all terms to the left:

2(3x+1)+4-3(4x+2)-5+4(5x-3)-5(6x-4)-(-29)=0

We add all the numbers together, and all the variables

2(3x+1)-3(4x+2)+4(5x-3)-5(6x-4)+28=0

We multiply parentheses

6x-12x+20x-30x+2-6-12+20+28=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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