2(3x+1)+3(x-4)=17

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Solution for 2(3x+1)+3(x-4)=17 equation: 



2(3x+1)+3(x-4)=17

We move all terms to the left:

2(3x+1)+3(x-4)-(17)=0

We multiply parentheses

6x+3x+2-12-17=0

We add all the numbers together, and all the variables

9x-27=0

We move all terms containing x to the left, all other terms to the right

9x=27

x=27/9

x=3

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