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2(3x)+2(2x+3)=3(5x-3)
We move all terms to the left:
2(3x)+2(2x+3)-(3(5x-3))=0
We multiply parentheses
23x+4x-(3(5x-3))+6=0
We calculate terms in parentheses: -(3(5x-3)), so:We add all the numbers together, and all the variables
3(5x-3)
We multiply parentheses
15x-9
Back to the equation:
-(15x-9)
27x-(15x-9)+6=0
We get rid of parentheses
27x-15x+9+6=0
We add all the numbers together, and all the variables
12x+15=0
We move all terms containing x to the left, all other terms to the right
12x=-15
x=-15/12
x=-1+1/4
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