2(3w+3)-4(5w-3)=w(w-3)-w(w+5)

Solution for 2(3w+3)-4(5w-3)=w(w-3)-w(w+5) equation:

2(3w+3)-4(5w-3)=w(w-3)-w(w+5)

We move all terms to the left:

2(3w+3)-4(5w-3)-(w(w-3)-w(w+5))=0

We multiply parentheses

6w-20w-(w(w-3)-w(w+5))+6+12=0


We calculate terms in parentheses: -(w(w-3)-w(w+5)), so:

w(w-3)-w(w+5)

We multiply parentheses

w^2-w^2-3w-5w

We add all the numbers together, and all the variables

-8w

Back to the equation:

-(-8w)


We add all the numbers together, and all the variables

-14w-(-8w)+18=0

We get rid of parentheses

-14w+8w+18=0

We add all the numbers together, and all the variables

-6w+18=0

We move all terms containing w to the left, all other terms to the right

-6w=-18

w=-18/-6

w=+3