2(3v-5)=(v-11-4)

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Solution for 2(3v-5)=(v-11-4) equation: 



2(3v-5)=(v-11-4)

We move all terms to the left:

2(3v-5)-((v-11-4))=0

We add all the numbers together, and all the variables

2(3v-5)-((v-15))=0

We multiply parentheses

6v-((v-15))-10=0



We calculate terms in parentheses: -((v-15)), so:

(v-15)

We get rid of parentheses

v-15

Back to the equation:

-(v-15)



We get rid of parentheses

6v-v+15-10=0

We add all the numbers together, and all the variables

5v+5=0

We move all terms containing v to the left, all other terms to the right

5v=-5

v=-5/5

v=-1

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