2(3v-5)-(-6+2v)=12

Solution for 2(3v-5)-(-6+2v)=12 equation:

Simplifying
2(3v + -5) + -1(-6 + 2v) = 12

Reorder the terms:
2(-5 + 3v) + -1(-6 + 2v) = 12
(-5 * 2 + 3v * 2) + -1(-6 + 2v) = 12
(-10 + 6v) + -1(-6 + 2v) = 12
-10 + 6v + (-6 * -1 + 2v * -1) = 12
-10 + 6v + (6 + -2v) = 12

Reorder the terms:
-10 + 6 + 6v + -2v = 12

Combine like terms: -10 + 6 = -4
-4 + 6v + -2v = 12

Combine like terms: 6v + -2v = 4v
-4 + 4v = 12

Solving
-4 + 4v = 12

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4v = 12 + 4

Combine like terms: -4 + 4 = 0
0 + 4v = 12 + 4
4v = 12 + 4

Combine like terms: 12 + 4 = 16
4v = 16

Divide each side by '4'.
v = 4

Simplifying
v = 4