2(3v-2)+6v+6=4(v-4)+2

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Solution for 2(3v-2)+6v+6=4(v-4)+2 equation: 



2(3v-2)+6v+6=4(v-4)+2

We move all terms to the left:

2(3v-2)+6v+6-(4(v-4)+2)=0

We add all the numbers together, and all the variables

6v+2(3v-2)-(4(v-4)+2)+6=0

We multiply parentheses

6v+6v-(4(v-4)+2)-4+6=0



We calculate terms in parentheses: -(4(v-4)+2), so:

4(v-4)+2

We multiply parentheses

4v-16+2

We add all the numbers together, and all the variables

4v-14

Back to the equation:

-(4v-14)



We add all the numbers together, and all the variables

12v-(4v-14)+2=0

We get rid of parentheses

12v-4v+14+2=0

We add all the numbers together, and all the variables

8v+16=0

We move all terms containing v to the left, all other terms to the right

8v=-16

v=-16/8

v=-2

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