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2(3v+2)+2=3(v+1)
We move all terms to the left:
2(3v+2)+2-(3(v+1))=0
We multiply parentheses
6v-(3(v+1))+4+2=0
We calculate terms in parentheses: -(3(v+1)), so:We add all the numbers together, and all the variables
3(v+1)
We multiply parentheses
3v+3
Back to the equation:
-(3v+3)
6v-(3v+3)+6=0
We get rid of parentheses
6v-3v-3+6=0
We add all the numbers together, and all the variables
3v+3=0
We move all terms containing v to the left, all other terms to the right
3v=-3
v=-3/3
v=-1
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