2(3u-4)+6u=40

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Solution for 2(3u-4)+6u=40 equation: 



2(3u-4)+6u=40

We move all terms to the left:

2(3u-4)+6u-(40)=0

We add all the numbers together, and all the variables

6u+2(3u-4)-40=0

We multiply parentheses

6u+6u-8-40=0

We add all the numbers together, and all the variables

12u-48=0

We move all terms containing u to the left, all other terms to the right

12u=48

u=48/12

u=4

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