2(3u-3)+4u+5=5(u-3)-2u

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Solution for 2(3u-3)+4u+5=5(u-3)-2u equation:



2(3u-3)+4u+5=5(u-3)-2u
We move all terms to the left:
2(3u-3)+4u+5-(5(u-3)-2u)=0
We add all the numbers together, and all the variables
4u+2(3u-3)-(5(u-3)-2u)+5=0
We multiply parentheses
4u+6u-(5(u-3)-2u)-6+5=0
We calculate terms in parentheses: -(5(u-3)-2u), so:
5(u-3)-2u
We add all the numbers together, and all the variables
-2u+5(u-3)
We multiply parentheses
-2u+5u-15
We add all the numbers together, and all the variables
3u-15
Back to the equation:
-(3u-15)
We add all the numbers together, and all the variables
10u-(3u-15)-1=0
We get rid of parentheses
10u-3u+15-1=0
We add all the numbers together, and all the variables
7u+14=0
We move all terms containing u to the left, all other terms to the right
7u=-14
u=-14/7
u=-2

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