2(3u+2)=7(u-3)+(u-5)

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Solution for 2(3u+2)=7(u-3)+(u-5) equation:


2(3u+2)=7(u-3)+(u-5)

We simplify the equation to the form, which is simple to understand
2(3u+2)=7(u-3)+(u-5)

Reorder the terms in parentheses
+(+6u+4)=7*(u-3)+(u-5)

Remove unnecessary parentheses
+6u+4=+7+*(+u-3+)+(+u-5+)

Reorder the terms in parentheses
+6u+4=+(+7u-21)+(u-5)

Remove unnecessary parentheses
+6u+4=+7u-21+(+u-5+)

Remove unnecessary parentheses
+6u+4=+7u-21+u-5

We move all terms containing u to the left and all other terms to the right.
+6u-7u-1u=-21-5-4

We simplify left and right side of the equation.
-2u=-30

We divide both sides of the equation by -2 to get u.
u=15

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